6v^2-9-60=0

Solution for 6v^2-9-60=0 equation:

6v^2-9-60=0

We add all the numbers together, and all the variables

6v^2-69=0

a = 6; b = 0; c = -69;
Δ = b2-4ac
Δ = 02-4·6·(-69)
Δ = 1656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1656}=\sqrt{36*46}=\sqrt{36}*\sqrt{46}=6\sqrt{46}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{46}}{2*6}=\frac{0-6\sqrt{46}}{12}
=-\frac{6\sqrt{46}}{12}
=-\frac{\sqrt{46}}{2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{46}}{2*6}=\frac{0+6\sqrt{46}}{12}
=\frac{6\sqrt{46}}{12}
=\frac{\sqrt{46}}{2}
$